Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2008-12-05 12:19:25

Danbee
Member
Registered: 2008-08-28
Posts: 21

Application of derivative

Find the right circular cylinder of greatest volume that can be contained in a sphere of radius 1

Offline

#2 2008-12-05 18:32:42

Jai Ganesh
Administrator
Registered: 2005-06-28
Posts: 48,428

Re: Application of derivative

I shall attempt this one without calculus!
The diamter of the cylinder and height of the cylinder would both be 1 unit each respectively.
Therefore, the volume of the cylinder would be


Since the diameter of the top and the base of the cylinder is 1 unit, the radius would be ½ unit.
Hence,

or

cubic units.

I ain't too sure though smile


It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

#3 2008-12-06 14:18:55

Danbee
Member
Registered: 2008-08-28
Posts: 21

Re: Application of derivative

That is not right

Offline

#4 2008-12-07 03:33:33

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: Application of derivative

If the cylinder has a radius of x, then I think its height is 2√(1-2x²).

So the volume would be 2πx²√(1-2x²).
Differentiate this and equate to 0 to find the best value of x.
It might be easier if you replace x² with t (for example) and work wrt. t instead. That won't change the answer.

Edit: The height in the post below me is right. That one was my initial thought, but then I started thinking about the equation of a sphere and got thrown off.


Why did the vector cross the road?
It wanted to be normal.

Offline

#5 2008-12-08 11:25:14

mathsmypassion
Member
Registered: 2008-12-01
Posts: 33

Re: Application of derivative

If the cylinder has  a radius of x then its height is 2√ (1-x ²). You can check this drawing a right-angled triangle having the hypotenuse the diagonal of the cyclic rectangle with dimensions x and height. So the volume would be V = 2πx²√ (1-x² ). You know what to do next.

Offline

Board footer

Powered by FluxBB