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I have been home sick, and i got the hw for math but i dont know how to do it.
"Determine whether each trinomial is a perfect square trinomial. If so factor it."
1. c² - 6c + 9
(That is C squared subtract six C plus nine)
thanks
3ddhomejoe
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A perfect square is something of the form (ax+b)². Your trinomial is monic (ie. there's no coefficient in front of the x²), so its perfect square form (if it had one) would be (x+b)², for some b.
The expanded form of this is x² + 2bx + b². By equating the x coefficients, you get 2b = -6. This implies that b = -3.
Now you check to make sure the constants match up. If they do then it's a perfect square trinomial, if they don't then it's not. (-3)² = 9, and so it's a match.
Therefore, x² - 6x + 9 is a perfect square trinomial and factoring it gives (x-3)².
Why did the vector cross the road?
It wanted to be normal.
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