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Why did the vector cross the road?
It wanted to be normal.
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Tank you mathsyperson but
let x=6/10
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Sorry, I'm not sure what you're getting at.
6/10 is a solution and is in my solution set, so there's no contradiction.
If you're hinting at a more elegant method of reaching the answer, I'm afraid I don't get that either.
Why did the vector cross the road?
It wanted to be normal.
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Perhaps hes hinting that your solution isnt wholly correct. x = 6⁄10 is NOT a solution. Also, you cant have x = 1. What is logarithm to base 1, anyway?
Anyway, log[sub]x[/sub] where x < 1 problematic. If x < 1, then you actually have log[sub]x[/sub]y > 0 when y < 1 and log[sub]x[/sub]y < 0 when y > 1. With this in mind, I think youll find that not only
is invalid but also
is a solution set as well.
Last edited by JaneFairfax (2007-12-23 01:00:39)
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Ah, fair enough. I made too many assumptions in the first step.
Why did the vector cross the road?
It wanted to be normal.
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Pages: 1