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#1 2007-02-27 07:16:27

kathreen
Guest

sigma

whats the value of this sigma :

1 ² - 2 ² + 3 ² - 4 ² + 5 ² - 6 ² + ... +199 ²

i really worked trying to solve it ... but all the doors were closed i tried to divide it into two and get they sigma of each one so the total is the answer but no way ...

who can help me or at least give me the idea and i'll be grateful

#2 2007-02-27 07:37:26

luca-deltodesco
Member
Registered: 2006-05-05
Posts: 1,470

Re: sigma

Last edited by luca-deltodesco (2007-02-27 07:38:18)


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#3 2007-02-27 07:48:08

kathreen
Guest

Re: sigma

luca-deltodesco thanks but i didnt get it ... can you explain more ?! with number if you dont mind

jane dont forget that we have positive and negative numbers so ...

#4 2007-02-27 07:54:28

kathreen
Guest

Re: sigma

thanks luca i think i got it ! thanks alot

#5 2007-02-27 08:02:40

kathreen
Guest

Re: sigma

i got the way but how to do it ?! sad sorry

#6 2007-02-27 08:10:48

kathreen
Guest

Re: sigma

kylekatarn wrote:

maybe you can split that sum into two sums: 'i' odd and 'i' even. Then you just have to sum two expressions not involving (-1)^i-1

i thought about it but i got some difficulity to write that in sigma ... can you help ?!

#7 2007-02-27 08:21:50

Sekky
Member
Registered: 2007-01-12
Posts: 181

Re: sigma

kylekatarn wrote:

maybe you can split that sum into two sums: 'i' odd and 'i' even. Then you just have to sum two expressions not involving (-1)^i-1

Like sigma i=1 to 99 of some function of 2i plus i from 1 to 100 of some function of 2i+1 (possibly reversed I can't care enough to think about it)

Nah, delta's way is far superior.

But change i-1 for i+1....for the sake of sake's sake.

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#8 2007-02-27 08:28:18

kathreen
Guest

Re: sigma

aha thanks sekky for saying that but its really hard for me to get out that in this way :

199
∑     = ( -1 ) ^ ( i + 1 ) × i ²
i=1

could you help me please ?!

#9 2007-02-27 10:25:47

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: sigma

Pairing up terms might well help you. (n+1)² - n² = 2n+1, so by pairing up consecutive terms (you can pair the first one with 0² without changing the result) you can simplify the summation quite a bit.


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#10 2007-02-28 07:18:36

RauLiTo
Member
From: Bahrain
Registered: 2006-01-11
Posts: 142

Re: sigma

you can write it like this :
(1 ² - 2 ²) + (3 ² - 4 ² ) + ( 5 ² - 6 ²) + ... +199 ²
-3 + - 7 + - 11 + ...

its a series now big_smile

or you can do it with sigma like this :

22eq0.jpg


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