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Solve 1/a = 1/b + 1/c
I think the first step is to multiply both sides of the equation by ABC.
(abc)(1/a) = (abc)(1/b + 1/c)
bc = ac + ab
Is this OK so far?
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In the right path.
It appears to me that if one wants to make progress in mathematics, one should study the masters and not the pupils. - Niels Henrik Abel.
Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.
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Solve 1/a = 1/b + 1/c
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sologuitar wrote:Solve 1/a = 1/b + 1/c
Thanks but I didn't ask you to solve for c.
I often find myself going through a textbook like walking in the park on a sunny day. I then reach a certain chapter or section that requires knowledge of all the previous math material I have learned or thought I learned. Confusion sets in to create a stumbling block that keeps me wondering if I truly learned anything at all in my previous math courses or chapters or sections that I just completed. Why does this happen? How do I keep myself from forgetting the earlier chapters or sections in math textbooks?
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