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Okay, so, having hopefully got myself re-acquainted with the very basics of differentiation, I now realise how much basic geometry I've forgotten (sigh - if only i still had my formula books ). Anyway, enough complaining, so I'm looking at the chain rule and rates of change and the first question I have is:
So, does anyone know where I've gone wrong?
Last edited by Au101 (2013-06-05 12:16:11)
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hi Au101,
Welcome back; nice to hear from you again.
I've read and re-read this problem and I cannot find anything wrong with your answer. Maybe the book answer is just a typo. It would be easy to type two 1s rather than two zeros. My brain to finger coordination does this to me all the time. With the answer expressed as a multiple of pi it's hard to see why 110 (not divisible be 4) would be correct.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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I am confused,since (i) wants rate depending on depth.so we should calculate dv/dh at h=5(which is 25π).correct me if i'm wrong.
Last edited by {7/3} (2013-06-05 19:39:52)
There are 10 kinds of people in the world,people who understand binary and people who don't.
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hi {7/3)
Rate is usually taken as wrt time. So asking for dV/dt
Also look at the units for the book answer.
This is what Au101 has done.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Ok.in that case shouldn't dV/dt be a function in terms of t,not h?
There are 10 kinds of people in the world,people who understand binary and people who don't.
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Well, h is a function of t, so it comes down to the same thing.
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
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Thanks
There are 10 kinds of people in the world,people who understand binary and people who don't.
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No problem.
Here lies the reader who will never open this book. He is forever dead.
Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment
The knowledge of some things as a function of age is a delta function.
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It's great to be back, bob bundy Thanks so much. I have a feeling you're right, I just didn't have enough confidence in my answer, but the book agrees with me that the answer to part (ii) is:
{7/3} and anonimnystefy, you're absolutely right. We know that h varies with t, specifically, it varies at the uniform rate of:
(As the question tells us.)
And we know that V varies with h, specifically, it varies at a rate of:
(According to my calculations)
We know, then, that V also varies with t, since it varies with h, which varies with t. Specifically, by the chain rule, it varies at a rate of:
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Just a very very quick point of confusion I'd like to clear up, if I may: I have the question:
And after some mathematics, I come up with the solution that the length l of NT is:
Which agrees with the answer book, except the answer book does not have the modulus sign. I just wanted to clear-up why I can simply get rid of the modulus signs in this case, since my rustiness even extends to calculations of distance
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hi Au101,
Because it is measuring distance and that cannot be negative. Without the || some values of t would give negative values for 4t^2 - 4t/3
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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So, surely, I should keep them? The answer book simply has
I had thought that maybe the answer book was giving a simplified answer, it's an old A-level book, but the syllabus was very different back then, so I'm never sure what I'm expected to know But looking at it, if I draw a graph, I don't think T can ever - on this graph - be above N on the y-axis, so - presumably - the distance can always be given by N - T, with no need to worry about what would happen if T were to occur above N, giving a negative distance?
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Maybe it depends on the way a question is worded. I've met some where the distance along the x axis of a particle from the origin is given as a function of t. For some t the distance comes out negative and you're supposed to interpret that as meaning the particle is to the left of (0,0) .
I doubt it would loose you marks either way.
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob
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Okay, thanks bob bundy I don't think I'll worry about it too much, I mean, I just want to get my calculus back to a good enough level to start looking at some new maths and physics &c., so it's just some general practice It's good for me to understand as much as possible though
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