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Why is the base of a log always positive?
We always see
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simply because logarithms on the reals are not defined for negative numbers:
since ln(-n) is not defined for reals, neither is log_(-n)x although as you have shown there are special cases where you can define it
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if you venture into the complex realm, then you can define logarithms for negative bases:
natural logarithm of a negative real is given by the multivalued function
with principal branch:
so you could then have for some negative n
which gives for n = 5 and x = 25
and then, although this certainly is NOT '2' the expected answer, it is still of use since
Infact, you 'can' get 2 as the result if you do not use the principal branch, and instead define the logarithm as:
which gives
you can see this since:
although note that only the principal branch version is guaranteed to retain the property:
Last edited by luca-deltodesco (2009-02-10 08:55:31)
The Beginning Of All Things To End.
The End Of All Things To Come.
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if you venture into the complex realm, then you can define logarithms for negative bases:
How is this?
Last edited by Identity (2009-02-10 16:38:53)
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luca-deltodesco wrote:if you venture into the complex realm, then you can define logarithms for negative bases:
How is this?
ln(x) is defined as being the inverse of e^x. Because e^x can only take on positive values, ln(x) can only be defined for positive numbers.
Now going to the complex case, we now have e^z, which Euler tells us is really:
It isn't too difficult to check that e^z hits every number in the complex plain except 0. Thus, we can define the inverse (i.e. log) there. However, e^z isn't 1-1, specifically e^(z+2*pi*i) = e^z. Because of this, we can only define an inverse of e^z on certain regions of the complex plane at a single time. Things unfortunately get a bit more complicated from there, but that's the gist.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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