Algebra

Jai Ganesh · 2006-02-26 22:51:50

A # 1

If x² + y² + z² = 50, xy + yz + xz = 47 and xyz = 60,
what is the value of
(i) x
(ii) y and
(iii) (x+y+z)³?

krassi_holmz · 2006-02-27 01:03:01

the numbers are {3,4,5}
12^3=1728

Jai Ganesh · 2006-02-27 01:52:40

good%20job.gif

krassi_holmz · 2006-02-27 03:11:00

Thanks.

Jai Ganesh · 2006-03-01 04:20:33

A # 2

For waht value of m is 2x³-x²-3mx-24 divisible by x-2?

krassi_holmz · 2006-03-01 04:40:22

m=2?

Jai Ganesh · 2006-03-01 16:09:19

|m|=2 would have been better! The answer is m=-2. Try again, krassi_holmz, probably you made a mistake somewhere.

Jai Ganesh · 2006-03-01 16:11:38

A # 3

If ax³+bx²+x-6 has (x+2) as a factor and leaves a remainder 4 when divided by (x-2), find the values of a and b.

Jai Ganesh · 2006-03-01 20:28:39

A # 4

The sum of two natural numbers is 8. Determine the numbers if the sum of their reciprocals is 8/15.

mathsyperson · 2006-03-02 04:52:57

A # 3
From the information given, we can deduce that f(-2) = 0 and f(2) = 4.

-8a + 4b -8 = 0
8a + 4b -4 = 4

Subtract the two equations:
16a -4 = -4
16a = 0
a = 0.

Add the two equations: 8b -12 = 4
8b = 16
b = 2.

f(x) = 2x²+x-6

A # 4
Calling the 2 numbers p and q, we know that p+q = 8, and that 1/p+1/q = 8/15.

Cross-multiplying the second equation gives (p+q)/pq = 8/15. We know that (p+q) = 8, so pq must be 15.

The numbers that add to give 8 and multiply to give 15 are 3 and 5.

Jai Ganesh · 2006-03-02 16:26:54

Well done, mathsyperson!

Jai Ganesh · 2006-03-02 17:29:28

A # 5

If one of the roots of the equation x²-3x+q=0 is twice the other, find the value of q.

Jai Ganesh · 2006-03-06 20:12:43

A # 6

If the ratio of the roots of the equation ax²-2ax+b=0 is equal to that of ax²-2cx+d=0, then which of the following is true?

(a) a²b=c²d (b) a²c=b²d

(c) a²d=c²b (d) d²b=c²a

Jai Ganesh · 2006-03-08 16:15:28

A # 7

Solve: (x²+1/x²) - 3(x-1/x)-2=0

amonjezi · 2006-03-10 20:09:52

y=4
and,y=-1

amonjezi · 2006-03-10 20:15:51

(x
+1/x^2)-3(x-1/x)-2+2-2=0

amonjezi · 2006-03-10 20:27:02

(x^2+1/x^2)-3(x-1/x)-2+2-2=0 then (x+1/x)^2-3(x-1/x)-4=0 if (x+1/x)=y y=4 and -1 now we solves (x+1/x)=4 and (x+1/x)=-1 these equaition very easy

amonjezi · 2006-03-11 01:17:49

hi ganesh
choice (a) or(c) are true

Eeyore · 2007-04-23 08:20:02

a7 1 and -1

Eeyore · 2007-04-23 08:41:04

A#5 q=2

bobbym · 2010-10-22 00:12:45

Hi ganesh;

soroban · 2011-02-12 07:37:00

. .

.

soroban · 2011-02-12 07:58:53

.

Jai Ganesh · 2011-02-13 01:06:44

Hi soroban,

I too get the same solutions. Well done!

G-man · 2011-03-02 05:54:20

Math Is Fun Forum

#1 2006-02-26 22:51:50

Algebra

#2 2006-02-27 01:03:01

Re: Algebra

#3 2006-02-27 01:52:40

Re: Algebra

#4 2006-02-27 03:11:00

Re: Algebra

#5 2006-03-01 04:20:33

Re: Algebra

#6 2006-03-01 04:40:22

Re: Algebra

#7 2006-03-01 16:09:19

Re: Algebra

#8 2006-03-01 16:11:38

Re: Algebra

#9 2006-03-01 20:28:39

Re: Algebra

#10 2006-03-02 04:52:57

Re: Algebra

#11 2006-03-02 16:26:54

Re: Algebra

#12 2006-03-02 17:29:28

Re: Algebra

#13 2006-03-06 20:12:43

Re: Algebra

#14 2006-03-08 16:15:28

Re: Algebra

#15 2006-03-10 20:09:52

Re: Algebra

#16 2006-03-10 20:15:51

Re: Algebra

#17 2006-03-10 20:27:02

Re: Algebra

#18 2006-03-11 01:17:49

Re: Algebra

#19 2007-04-23 08:20:02

Re: Algebra

#20 2007-04-23 08:41:04

Re: Algebra

#21 2010-10-22 00:12:45

Re: Algebra

#22 2011-02-12 07:37:00

Re: Algebra

#23 2011-02-12 07:58:53

Re: Algebra

#24 2011-02-13 01:06:44

Re: Algebra

#25 2011-03-02 05:54:20

Re: Algebra

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