Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2013-01-08 02:47:06

mukesh
Member
Registered: 2010-07-18
Posts: 31

co-ordinate geometry

using co-ordinate geometry show that median of an equilatral triangle is perpendiculur to its opposite side.
Plse help me sir

Offline

#2 2013-01-08 04:23:29

Bob
Administrator
Registered: 2010-06-20
Posts: 10,623

Re: co-ordinate geometry

hi mukesh,

Coordinate geometry is an unusual way to do this but OK; it can be done.

Firstly, you need to choose your triangle.

I'd keep things simple by having the base going from (0,0) to (2,0).

That makes the midpoint of the base at (1,0)

The vertex will be at (2cos60, 2sin60) = (1,√ 3)

The median joins the midpoint of the base to the vertex so that is the line x=1, which is at right angles to the base.

Bob


Children are not defined by school ...........The Fonz
You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you!  …………….Bob smile

Offline

Board footer

Powered by FluxBB