solve

tony123 · 2007-11-22 20:20:45

Last edited by tony123 (2007-11-22 20:22:52)

esatpllana · 2007-11-22 20:50:55

I'm interesting how to solve this can anyone solve this

gyanshrestha · 2007-11-22 22:57:37

let

then above simplifies to
..........1
.....2
..........3
eq. (1) and (2) give ralation in a and b
then it is difficult to factorize eq. (3)
can we factorize the third equation then i think we can solve.

NullRoot · 2007-11-23 02:19:58

The simplest answer is x, y, z = 1.

If you want x, y, z to have different values and you want those values to work for all three equations, then here's the messy way...

We know:

So:

If you subtract the left side from the right, then you have:

Because the square roots on the left side can be either positive or negative, you don't know whether you will increase or decrease the number on the right side.
Using the third equation, we can deduce:

So:

And using the subtraction again:

So if you pick a value for X and Y, you might be able to work out what the corresponding Z value is.
For example, I've picked x=1, y=2. If we substitute these values and simplify then, we end up with:

We know √z = 3 - √y - √x from the first equation, so we can substitute in that:

So, dividing and then rearranging:

Because of the plus-minuses and the square roots, I think the right side might have 256 possible combinations (some combos will have the same value, though). Since z²+z is quadratic, I think that each of those combinations could have two answers.

So... rather than bother with any of the above, x=1, y=1, z=1.

esatpllana · 2007-11-23 06:50:38

thnx bro i will try to solve this in my way thnx

Math Is Fun Forum

#1 2007-11-22 20:20:45

solve

#2 2007-11-22 20:50:55

Re: solve

#3 2007-11-22 22:57:37

Re: solve

#4 2007-11-23 02:19:58

Re: solve

#5 2007-11-23 06:50:38

Re: solve

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