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I'm having lots of problems with probability questions.
Could you help me solve this? Thank you.
4 different letters are to be sent to 4 different addresses. For each letter there is an envelope with its correct address. If the 4 letters are to be put into the 4 envelopes at random, what it the probability that ony 1 letter will be put into the envelope with its correct address?
thank you
Last edited by simone (2007-10-15 23:24:47)
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Write out the permutations.
AinA BinB CinC DinD
Let's make four columns labeled inA inB inC and inD envelope.
inA inB inC inD
a b c d
d c b a
c a b d (d in D, other 3 wrong envelope)
d b a c (b in B)
b d a c
c a d b
a d b c (a in A)
c b d a (b in B)
b a c d (c and d right, so ignore)
d c a b
b d c a (c in C)
a c d b (a in A)
d a b c
c b a d (ignore 2 right)
b c d a
a d c b (ignore 2 right)
c d a b
b a d c
a b d c (ignore 2 right)
c d b a
a c b d (ignore 2 right a & d)
d b c a (ignore 2 right b & c)
d a c b (c in C)
b c a d (d in D)
8 out of 24 are only 1 right & 3 wrong.
6 out of 24 are 2 right & 2 wrong.
9 out of 24 are none right & 4 wrong.
1 out of 24 is all 4 right & none wrong!!
8 + 6 + 9 + 1 = 24
4 x 3 x 2 = 24
Last edited by John E. Franklin (2007-10-16 03:42:19)
igloo myrtilles fourmis
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