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I have the function
Plot3D[Sin[47^{64.9/Cos[90.469+x/y]}]{x,-5,5},{y,-10,10}]
And I want to graph it in 3D. But Mathematica won't graph it. It just doesn't seem to respond. What's going on? Am I doing something wrong with the brackets?
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Hi;
There are 2 immediate problems with your use of the 3DPlot3D command.
] {x, -5, 5}, there should be a comma like this ] ,{x, -5, 5}
and
{64.9/Cos[90.469 + x/y]}, mathematica uses braces like that for parameters and lists but always uses parentheses for order of operations. So that should be (64.9/Cos[90.469 + x/y])
One question:
You wrote 90.469 + x/y which mathematica will interpret as
Is that what you intended? I only ask because
works in the ranges you gave.In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Yes.
I was using the online version of Mathematica, and I'm wondering if there is a way to delete your notebook cells...
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Never mind, I figured it out.
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Did you find your errors or was it something else?
Did you get it to plot?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Yes, I got the plot to work! (Yay!)
Although nothing showed up, implying I need to change the domain and range of the plot to get it to actually plot. Any ideas?
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Plot3D[Evaluate[Sin[47^(64.9/Cos[90.469 + x/y])]], {x, -5, 5}, {y, -2,2}]
Use the cursor to rotate it around.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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How do you add greek symbols such as
into your plots? Simply entering Theta doesn't work...Offline
Hi;
Escape key th escape key.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Okay, thanks. I also realized \[Theta] will also work...
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Yes, check the help and you will usually find all you need.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Mathematica SE is also helpful.
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They sure are and I was going to recommend them.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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There is a simple trick to keep that from happening.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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That usually gets an admonishment from several members. The best way, is just mention mathematica in the question a couple of times.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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I learned that you can factor
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Hi;
Factor[a^4 + b^4, Extension -> Sqrt[2]] // TraditionalForm
Check in the Help for Factor to get much more.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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That's so cool!
I now have accomplished factoring
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Factor[x^8 + 4 x^7 - 10 x^6 - 54 x^5 + 9 x^4 + 226 x^3 + 125 x^2 - 301 x - 269, Extension -> Sqrt[5]]
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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It then turns out that you can factor the remaining quartics into quadratics by having them factor over the extension of Sqrt[13+4 Sqrt[5]] and Sqrt[13-4 Sqrt[5]].
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Factor[x^8 + 4 x^7 - 10 x^6 - 54 x^5 + 9 x^4 + 226 x^3 + 125 x^2 - 301 x - 269,
Extension -> {Sqrt[13 + 4 Sqrt[5]] , Sqrt[13 - 4 Sqrt[5]]}]
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Hm... why can't Mathematica not solve
Solve[{c, a+c^2 d, a^2+b+c d^2+c^2 e, a^2 b+ b^2+ d^2 e+c e^2, a^3+6 a b+d^3+6 c d e, a b^2+3 d e^2, b^3+e^3}=={h,f, f^2+g+h^2 t, f^2 g+g^2+h t^2, f^3+6 f g, f g^2, g^3+t^3}]
It just sits there loading! I'm trying to find the unknown variables... Is there something wrong with the syntax?
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Hi;
For one thing, you have 8 unknowns and only 7 equations. Did you leave one out?
Be back after I eat something.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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