How do I figure this?

misheeru · 2010-03-09 08:45:03

The question is can I conclude that arc AB = arc BC??

misheeru · 2010-03-09 08:46:03

I have a few like this so anyhelp is GREATLY appreciated... arigato

Sarah Rebekah 13 · 2010-03-09 10:26:01

Misheeru A Tutor Can Help you With Thats Geometry.

misheeru · 2010-03-09 10:44:12

well Rebekah I dont go to a regular school so if I need a tutor I will have to pay for one and since I don't have a job at the moment I ask for help here...

bobbym · 2010-03-09 13:37:57

Hi misheeru;

No, I don't think you can. Not without more information.

soroban · 2010-03-09 14:24:54

              B
              o * *
          *     \     *  C
        *         \     o
       *            \ /  *
                    / \  
      *           /     \ *
      *         /         o D
      *       /           *
            /
       *  /              *
        o               *
      A   *           *
              * * *

.

Devantè · 2010-03-09 18:22:45

You'd need more information. It looks like arc AB is bigger than arc BC, but to be sure you'd need annotations.

Sarah Rebekah 13 · 2010-03-10 03:35:26

Im Sorry Misheeru

misheeru · 2010-03-10 05:26:31

ok thanks guys.

Is there a rule for this.. All of the problems on this page ask me if i can conlclude that they are equal, so is there a specific on how much info i need to conclude that they are equal?

Like this one, since it says the length of both I have the info i need right?

Last edited by misheeru (2010-03-10 05:28:09)

bobbym · 2010-03-10 05:40:40

Hi misheeru;

(ii) In equal circles (or in same circle), equal chords cut off equal arcs, and conversely; in equal circles (or in same circle), if two arcs are equal then their chords are equal.

arc AB = arc BC

misheeru · 2010-03-10 07:36:01

ok how about this?

its asking me if:

RS is tangent to circle A at X.

I don't really understand this tangent stuff.....

Last edited by misheeru (2010-03-10 07:36:54)

misheeru · 2010-03-10 07:39:46

Since the circle is inscribed in triangle and the circle touches all of the sides, aren't all the sides tangent to the circle?

John E. Franklin · 2010-03-10 22:02:27

Yes, I believe you are right, they are all tangent sides to the circle.

misheeru · 2010-03-11 06:05:20

ok thanks john e.!!!!

misheeru · 2010-03-11 07:09:57

Also..

What is the measure of an angle formed by two secants intersecting inside the circle equals?

is it ½ the sum of the intercepted arcs?

misheeru · 2010-03-11 07:11:53

alos the diameter of a cirle is twice the radii right?

So for this the answer is RS if it is asking me wut the diameter of A is?

Also wut is the common tangents in this?

Last edited by misheeru (2010-03-11 07:13:13)

misheeru · 2010-03-11 07:28:10

I am stuck on this as well.

it is a true or false question??

The measure of angle CAD is (0.3)(arc GE minus arc CD)

Monox D. I-Fly · 2017-09-26 18:22:54

misheeru wrote:

alos the diameter of a cirle is twice the radii right?

yes

misheeru wrote:

So for this the answer is RS if it is asking me wut the diameter of A is?

yes

misheeru wrote:

Also wut is the common tangents in this?

CD

Math Is Fun Forum

#1 2010-03-09 08:45:03

How do I figure this?

#2 2010-03-09 08:46:03

Re: How do I figure this?

#3 2010-03-09 10:26:01

Re: How do I figure this?

#4 2010-03-09 10:44:12

Re: How do I figure this?

#5 2010-03-09 13:37:57

Re: How do I figure this?

#6 2010-03-09 14:24:54

Re: How do I figure this?

#7 2010-03-09 18:22:45

Re: How do I figure this?

#8 2010-03-10 03:35:26

Re: How do I figure this?

#9 2010-03-10 05:26:31

Re: How do I figure this?

#10 2010-03-10 05:40:40

Re: How do I figure this?

#11 2010-03-10 07:36:01

Re: How do I figure this?

#12 2010-03-10 07:39:46

Re: How do I figure this?

#13 2010-03-10 22:02:27

Re: How do I figure this?

#14 2010-03-11 06:05:20

Re: How do I figure this?

#15 2010-03-11 07:09:57

Re: How do I figure this?

#16 2010-03-11 07:11:53

Re: How do I figure this?

#17 2010-03-11 07:28:10

Re: How do I figure this?

#18 2017-09-26 18:22:54

Re: How do I figure this?

Board footer