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#1 2007-05-01 22:16:49

Neela2
Guest

function

The graph of the function f(x) = 3x-4 intercepts the x-axis at A and y-axis at B.

Point A: (4/3,0)
Point B: (0, -4)

I'm now asked to find area of triangle OAB where O is the origen.

since its rightangled I used the 0.5 * base * height and obtained 8/3 as the area.

However, the result in the back of the book wants me to get 8/3 squareroot(x-4) + 3

Where does the last part come from?

Thanks

#2 2007-05-02 01:59:04

Dross
Member
Registered: 2006-08-24
Posts: 325

Re: function

Neela2 wrote:

However, the result in the back of the book wants me to get 8/3 squareroot(x-4) + 3

There's certainly no reason to have that result - 8/3 is correct.

It might be a typo, but have you checked everything else? (i.e. read the question correctly, made sure you're looking at the right answer - all the trivial stuff you might not think to check)


Bad speling makes me [sic]

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