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#1 Re: Help Me ! » another tricky integral » 2009-08-30 22:24:20

ac

Hi Bobbym,

Thank you, for your answer.


it is just the notation...

And yes, the limits of integration are from -∞ to ∞.

Thanks!

#2 Re: Help Me ! » another tricky integral » 2009-08-28 23:36:45

ac

Hi Bobbym,

You are right, the function is 1D, but it is easy to increase dimensions...

My goal is not to "get the job done", but to get the job done in a smart way... wink the goal is a closed form...

Do you think IBP can help in this case? any suggestion?

Thanks

#3 Re: Help Me ! » another tricky integral » 2009-08-28 20:15:11

ac

Hi Bobbym,

Thank you!

Numerical integration and asymptotic analysis.

If


have multiple dimensions...
Well I have to go to a casino in Monte Carlo... wink

or visit Laurent series and 

function...
asymptotic analysis, I wasn't looking in that direction... THANK YOU!

Can I ask for a good book in that subject?

#4 Re: Help Me ! » Simple question about two real variables » 2009-08-28 08:54:25

ac

you only have trivial solutions for your problem...

x=y=1 or x=y=0 with any a

#5 Re: Help Me ! » roots of equation » 2009-08-28 08:25:57

ac

Can I say that a periodic function has the same value in infinite multiple values?

you can look to


as a circle, one perspective of a periodic function...

in that sense, you have infinite multiple time values with the same angle value, the solution of your equation...

If you don't reduce the angle to a circle you will count the rotations, coded in the angle value... but it is only a different representation of the periodic function... the value of the function is the same...

hope this is useful... cool

#6 Re: Help Me ! » another tricky integral » 2009-08-28 07:40:54

ac

Hi George,

Thank you for your interest.

Do I need to have a use for it?
I'm trying to solve this integral just as an exercise.

Is it impossible?

#7 Re: Help Me ! » another tricky integral » 2009-08-28 07:34:54

ac

Hi Bobbym,

Thank you for your answer.

You can look to the function and if it is normalized, you have a probability density function... correct.

About the Gaussian, all the fun is in u2 and s2, without them you don't have the square root of a sum, the other part of the fun...

Is it impossible?

#8 Help Me ! » another tricky integral » 2009-08-19 23:13:16

ac
Replies: 11

Dear all,

I'm trying to solve this integral:

with


constants and real

Please, help me!

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