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Hi;
What did you do for the first one?
Having trouble with this exact problem. Help?
Can you help me with this problem as well?
Equilateral triangle ABC has centroid G. Triangle A'B'C' is the image of triangle ABC upon a dilation with center G and scale factor -2/3. Let K be the area of the region that is within both triangles. Find K/[ABC].
I tried solving it in Geogebra but I think I screwed up somewhere.
Actually I've solved 1. The answer was 152.
Still not certain about no. 2, however.
1. Two lines \ell and m intersect at O at an angle of 28^\circ. Let A be a point inside the acute angle formed by \ell and m. Let B and C be the reflections of A in lines \ell and m, respectively. Find the number of degrees in \angle BAC.
2. A laser is shot from vertex A of square ABCD of side length 1, towards point P on \overline{BC} so that BP = 3/4. The laser reflects off the sides of the square, until it hits another vertex, at which point it stops. What is the length of the path the laser takes?
Thanks!
You're welcome.
So did you get it right? / or if not yet submitted, do you want to post your answer?
Bob
I'm working on the same problem.
Is the answer not 220?
Let the incircle of triangle ABC be tangent to sides BC, AC, and AB at D, E, and F, respectively. Prove that triangle DEF is acute.
I believe these are similar triangles...
hi SPARKS_CHAN
These can all be done using this property of circles http://www.mathisfunforum.com/viewtopic.php?id=17799 post 6
You will also need isosceles triangles and angles along a straight line = 180.
Q1. Mark the centre of the circle as point C. Join K, M, Q, and R to C with radius lines.
Then, for example, MCK = 130, and MRK = 65.
Keep working around the diagram using all the above rules to work out every angle.
Q2. Similarly, call the centre of the small circle point C. Join AC and BC. Once again use the angle properties of a circle.
Q3. Same again. I used the property to work out AOE and COF, and gradually progressed round the diagram working out every angle.
Hope that's enough of a hint. Post back if you need more.
Bob
For (1) I'm still confused how you get RPK.
EDIT: Nevermind, I got it!
In the figure, if MR=MK, the measure of arc MK is 130 degrees, and measure of arc MQ is 28 degrees, then what is angle RPK, in degrees?
Points A and B are on circle O such that arc AB is 80 degrees. A circle is constructed that passes through A, B, and O. Find the measure of arc AOB on this circle.
In the figure below, EF is a diameter of the circle. What is the measure of angle ABC, in degrees?
Got the answer for 1!
It's sqrt10:1.
Can someone explain to me why the answer to number one isn't 2:1?
1) In the figure with four circles below, let A_1 be the area of the smallest circle, let A_2 be the area of the region inside the second-smallest circle but outside the smallest circle, and so on. If A_1 : A_2 : A_3 : A_4 = 1 : 2 : 3 : 4, then find the ratio of the largest radius to the smallest radius.
2) In triangle ABC, AB = 5, AC = 6, and BC = 7. Circles are drawn with centers A, B, and C, so that any two circles are externally tangent. Find the sum of the areas of the circles.
3) Let ABCD be a square of side length 4. Let M be on side BC such that CM = 1, and let N be on side AD such that DN = 1. We draw the quarter-circle centered at A.
Let x and y denote the areas of the shaded regions, as shown. Find x - y.
Ok Hint for Q2.
Extend CB to a point E somewhere on the line.
AB cuts two parallels, so DAB = ABE = 43. ( some call this 'alternate angles' but I've also seen it as 'Z-angles' )
Hope that helps.
Bob
I got question 2!
The answer is 32.
I've solved 3 as well. The answer was 44.
I GOT IT!
Here's the logic:
1 + 1 + 1 + 1 = fouR
2 + 2 + 2 + 2 = eighT
3 + 3 + 3 + 3 = twelvE
4 + 4 + 4 + 4 = sixteeN
5 + 5 + 5 + 5 = twentY
okay, I made a real account.
The answer to 1 should be 12, since the bases are 10 and 14.
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